What is expand [(2x-3)(2x+3)]^2 ?

The solution to expand [(2x-3)(2x+3)]^2 is 16x^4-72x^2+81

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expand [(2x-3)(2x+3)]^2

expand

[(2 x - 3) (2 x + 3)]^{2}

16 x^{4} - 72 x^{2} + 81

Solution steps

((2 x - 3) (2 x + 3))^{2}

Expand

(2 x - 3) (2 x + 3) : 4 x^{2} - 9

= (4 x^{2} - 9)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = 4 x^{2}, b = 9

= (4 x^{2})^{2} - 2 \cdot 4 x^{2} \cdot 9 + 9^{2}

Simplify

(4 x^{2})^{2} - 2 \cdot 4 x^{2} \cdot 9 + 9^{2} : 16 x^{4} - 72 x^{2} + 81

= 16 x^{4} - 72 x^{2} + 81

(3 x^{2} + 6 x + 1)^{5}

5 x^{3} y (6 x y^{5})

\frac{( 3 x - y ) ^{2}}{81}

\frac{x ^{3}}{2 ( x ^{2} - 4 )}

sin (x) sec (x)

What is expand [(2x-3)(2x+3)]^2 ?
The solution to expand [(2x-3)(2x+3)]^2 is 16x^4-72x^2+81