What are the solutions to the equation 3+x^2=12 ?

The solutions to the equation 3+x^2=12 are x=3,x=-3

Find the zeros of 3+x^2=12

The zeros of 3+x^2=12 are x=3,x=-3

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3 + x^{2} = 12

x = 3, x = - 3

Solution steps

3 + x^{2} = 12

Move

3

to the right side

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

\frac{5 x ^{7} y ^{8}}{x ^{2} y ^{8}}

12.5 + 3 x = 20

- x^{2} + 4 x = 9

∣ x - 2 ∣ = ∣ x - 4 ∣

\frac{x - 9}{3} = - 7

What are the solutions to the equation 3+x^2=12 ?
The solutions to the equation 3+x^2=12 are x=3,x=-3
Find the zeros of 3+x^2=12
The zeros of 3+x^2=12 are x=3,x=-3