What is expand 2(x^2-3x+8)^2 ?

The solution to expand 2(x^2-3x+8)^2 is 2x^4-12x^3+50x^2-96x+128

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expand 2(x^2-3x+8)^2

expand

2 (x^{2} - 3 x + 8)^{2}

2 x^{4} - 12 x^{3} + 50 x^{2} - 96 x + 128

Solution steps

2 (x^{2} - 3 x + 8)^{2}

(x^{2} - 3 x + 8)^{2} = x^{4} - 6 x^{3} + 25 x^{2} - 48 x + 64

= 2 (x^{4} - 6 x^{3} + 25 x^{2} - 48 x + 64)

Distribute parentheses

= 2 x^{4} + 2 (- 6 x^{3}) + 2 \cdot 25 x^{2} + 2 (- 48 x) + 2 \cdot 64

Apply minus-plus rules

+ (- a) = - a

= 2 x^{4} - 2 \cdot 6 x^{3} + 2 \cdot 25 x^{2} - 2 \cdot 48 x + 2 \cdot 64

Simplify

2 x^{4} - 2 \cdot 6 x^{3} + 2 \cdot 25 x^{2} - 2 \cdot 48 x + 2 \cdot 64 : 2 x^{4} - 12 x^{3} + 50 x^{2} - 96 x + 128

= 2 x^{4} - 12 x^{3} + 50 x^{2} - 96 x + 128

\frac{3}{( 3 x + c ) ^{3}}

x (y) δ (y - 5)

A (2, - 1) B (5, 4)

\frac{( y - z ) ^{2} - x}{2}

(7 + 4 i, 1 + i) (- 9 i, 1 - 2 i)

What is expand 2(x^2-3x+8)^2 ?
The solution to expand 2(x^2-3x+8)^2 is 2x^4-12x^3+50x^2-96x+128