What is expand 8(r(x)cos(x)+r(x)sin(x)=9) ?

The solution to expand 8(r(x)cos(x)+r(x)sin(x)=9) is 8cos(x)r(x)+8sin(x)r(x)=9

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expand 8(r(x)cos(x)+r(x)sin(x)=9)

expand

8 (r (x) cos (x) + r (x) sin (x) = 9)

8 cos (x) r (x) + 8 sin (x) r (x) = 9

Solution steps

8 (r (x) cos (x) + r (x) sin (x) = 9)

= 8 (cos (x) r (x) + 9 = sin (x) r (x))

Apply the distributive law:

a (b + c) = ab + a c

a = 8, b = r (x) cos (x), c = r (x) sin (x) = 9

8 r (x) cos (x) + 8 r (x) sin (x) = 9

8 cos (x) r (x) + 8 sin (x) r (x) = 9

\frac{3 x}{( x + 2 ) ( x + 3 ) ( x + 1 )}

\frac{8 x ( 5 x + 7 )}{( 7 x - 5 ) ^{2}}

\frac{n ( n + 1 )}{n + 2}

\frac{1}{2 ( 4 x - 10 )}

(x + y = 5,) - (x - y = 1)

What is expand 8(r(x)cos(x)+r(x)sin(x)=9) ?
The solution to expand 8(r(x)cos(x)+r(x)sin(x)=9) is 8cos(x)r(x)+8sin(x)r(x)=9