What is expand 1/2 (-2x^1-x^2=0) ?

The solution to expand 1/2 (-2x^1-x^2=0) is -(x^2)/2-x=0

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expand 1/2 (-2x^1-x^2=0)

expand

\frac{1}{2} (- 2 x^{1} - x^{2} = 0)

- \frac{x ^{2}}{2} - x = 0

Solution steps

\frac{1}{2} (- 2 x^{1} - x^{2} = 0)

= \frac{1}{2} (- 2 x^{1} - 0 = x^{2})

Apply the distributive law:

a (b - c) = ab - a c

a = \frac{1}{2}, b = - 2 x^{1}, c = x^{2} = 0

\frac{1}{2} (- 2 x^{1}) - \frac{1}{2} x^{2} = 0

Apply minus-plus rules

+ (- a) = - a

- 2 \cdot \frac{1}{2} x^{1} - \frac{1}{2} x^{2} = 0

Expand

- 2 \cdot \frac{1}{2} x^{1} - \frac{1}{2} x^{2} : - \frac{x ^{2}}{2} - x

- \frac{x ^{2}}{2} - x = 0

\frac{2 ( 45 + 8885 )}{49}

\frac{32 ( x + 1 ) ( 2 x + 1 )}{3 x ^{2}}

(x + d x) (- y cos (x))

- 1 (a + b = x + 2) - 1

- \frac{1}{s ^{2} ( s + 1 )}

What is expand 1/2 (-2x^1-x^2=0) ?
The solution to expand 1/2 (-2x^1-x^2=0) is -(x^2)/2-x=0