What is expand x^2(c_{1}(2ln(x)+3)) ?

The solution to expand x^2(c_{1}(2ln(x)+3)) is 2c_{1}x^2ln(x)+3c_{1}x^2

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expand x^2(c_{1}(2ln(x)+3))

expand

x^{2} (c_{1} (2 ln (x) + 3))

2 c_{1} x^{2} ln (x) + 3 c_{1} x^{2}

Solution steps

x^{2} (c_{1} (2 ln (x) + 3))

Remove parentheses:

(a) = a

= x^{2} c_{1} (2 ln (x) + 3)

= c_{1} x^{2} (2 ln (x) + 3)

Apply the distributive law:

a (b + c) = ab + a c

a = x^{2} c_{1}, b = 2 ln (x), c = 3

= x^{2} c_{1} \cdot 2 ln (x) + x^{2} c_{1} \cdot 3

= 2 c_{1} x^{2} ln (x) + 3 c_{1} x^{2}

(1 + x - 2 x^{2})^{6}

(x + 3 y = 9,) (x - 3 y = - 3)

R (9, 8) S (- 7, - 9)

(x^{2} + 2) \circ \frac{1}{x}

\frac{2}{( s + 1 ) ^{3}}

What is expand x^2(c_{1}(2ln(x)+3)) ?
The solution to expand x^2(c_{1}(2ln(x)+3)) is 2c_{1}x^2ln(x)+3c_{1}x^2