What is expand (3x-2)/(x(x-2)(x+1)(x+3)) ?

The solution to expand (3x-2)/(x(x-2)(x+1)(x+3)) is (3x-2)/(x^4+2x^3-5x^2-6x)

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expand (3x-2)/(x(x-2)(x+1)(x+3))

expand

\frac{3 x - 2}{x ( x - 2 ) ( x + 1 ) ( x + 3 )}

\frac{3 x - 2}{x ^{4} + 2 x ^{3} - 5 x ^{2} - 6 x}

Solution steps

\frac{3 x - 2}{x ( x - 2 ) ( x + 1 ) ( x + 3 )}

Expand

x (x - 2) (x + 1) (x + 3) : x^{4} + 2 x^{3} - 5 x^{2} - 6 x

= \frac{3 x - 2}{x ^{4} + 2 x ^{3} - 5 x ^{2} - 6 x}

\frac{- x + 1}{5 ( x + 2 )}

2^{x (x - 1)}

\frac{2}{s ( s ^{2} + 2 s + 2 )}

\frac{( y + 1 ) ^{2}}{2}

\frac{x - 5}{( x - 1 ) ( x + 1 )}

What is expand (3x-2)/(x(x-2)(x+1)(x+3)) ?
The solution to expand (3x-2)/(x(x-2)(x+1)(x+3)) is (3x-2)/(x^4+2x^3-5x^2-6x)