What is expand ((θ-X_{2}θ^3)^2)/2 ?

The solution to expand ((θ-X_{2}θ^3)^2)/2 is (θ^2)/2-θ^4X_{2}+(θ^6X_{2}^2)/2

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expand ((θ-X_{2}θ^3)^2)/2

expand

\frac{( θ - X _{2} θ ^{3} ) ^{2}}{2}

\frac{θ ^{2}}{2} - θ^{4} X_{2} + \frac{θ ^{6} X _{2}^{2}}{2}

Solution steps

\frac{( θ - X _{2} θ ^{3} ) ^{2}}{2}

(θ - X_{2} θ^{3})^{2} = θ^{2} - 2 θ^{4} X_{2} + θ^{6} X_{2}^{2}

= \frac{θ ^{2} - 2 θ ^{4} X _{2} + θ ^{6} X _{2}^{2}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{θ ^{2} - 2 θ ^{4} X _{2} + θ ^{6} X _{2}^{2}}{2} = \frac{θ ^{2}}{2} - \frac{2 θ ^{4} X _{2}}{2} + \frac{θ ^{6} X _{2}^{2}}{2}

= \frac{θ ^{2}}{2} - \frac{2 θ ^{4} X _{2}}{2} + \frac{θ ^{6} X _{2}^{2}}{2}

Divide the numbers:

\frac{2}{2} = 1

= \frac{θ ^{2}}{2} - θ^{4} X_{2} + \frac{θ ^{6} X _{2}^{2}}{2}

(- y^{2} + 1) d x

(x^{2} + x - 2)^{5}

(1, 2, - 2) \cdot (x, x^{2}, x^{3})

\frac{x + 4}{x ( x + 10 )}

(x - 1) e^{x - 1}

What is expand ((θ-X_{2}θ^3)^2)/2 ?
The solution to expand ((θ-X_{2}θ^3)^2)/2 is (θ^2)/2-θ^4X_{2}+(θ^6X_{2}^2)/2