What are the solutions to the equation 2x^2-7x-4=0 ?

The solutions to the equation 2x^2-7x-4=0 are x=4,x=-1/2

Find the zeros of 2x^2-7x-4=0

The zeros of 2x^2-7x-4=0 are x=4,x=-1/2

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2 x^{2} - 7 x - 4 = 0

x = 4, x = - \frac{1}{2}

Solution steps

2 x^{2} - 7 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 4) = 9

x_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 2}

x = \frac{- ( - 7 ) + 9}{2 \cdot 2} : 4

x = \frac{- ( - 7 ) - 9}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 4, x = - \frac{1}{2}

e^{- l n (t)}

- 2 x + 7 = 3

\frac{12}{4} \cdot \frac{6}{3} \cdot \frac{8}{9}

(3) (- 2) (- 4)

- ∣ 7 w - 5 ∣ - 2 = 3

What are the solutions to the equation 2x^2-7x-4=0 ?
The solutions to the equation 2x^2-7x-4=0 are x=4,x=-1/2
Find the zeros of 2x^2-7x-4=0
The zeros of 2x^2-7x-4=0 are x=4,x=-1/2