What is expand ((x+3)(x-2))/((x+1)(x-4)) ?

The solution to expand ((x+3)(x-2))/((x+1)(x-4)) is (x^2+x-6)/(x^2-3x-4)

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expand ((x+3)(x-2))/((x+1)(x-4))

expand

\frac{( x + 3 ) ( x - 2 )}{( x + 1 ) ( x - 4 )}

\frac{x ^{2} + x - 6}{x ^{2} - 3 x - 4}

Solution steps

\frac{( x + 3 ) ( x - 2 )}{( x + 1 ) ( x - 4 )}

Expand

(x + 1) (x - 4) : x^{2} - 3 x - 4

= \frac{( x + 3 ) ( x - 2 )}{x ^{2} - 3 x - 4}

Expand

(x + 3) (x - 2) : x^{2} + x - 6

= \frac{x ^{2} + x - 6}{x ^{2} - 3 x - 4}

\frac{9 ( 1 - 40 b - 56 c )}{8}

π (2 x + π)^{2}

\frac{8}{( 3 x - 4 ) ^{2}}

\frac{x + 4}{x ( x + 12 )}

\frac{d}{d t} ((x) (2 t + 2 t^{3}))

What is expand ((x+3)(x-2))/((x+1)(x-4)) ?
The solution to expand ((x+3)(x-2))/((x+1)(x-4)) is (x^2+x-6)/(x^2-3x-4)