What is expand 1/((2z+1)(z+1)(z+0.5)) ?

The solution to expand 1/((2z+1)(z+1)(z+0.5)) is 1/(2z^3+4z^2+2.5z+0.5)

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expand 1/((2z+1)(z+1)(z+0.5))

expand

\frac{1}{( 2 z + 1 ) ( z + 1 ) ( z + 0.5 )}

\frac{1}{2 z ^{3} + 4 z ^{2} + 2.5 z + 0.5}

Solution steps

\frac{1}{( 2 z + 1 ) ( z + 1 ) ( z + 0.5 )}

Expand

(2 z + 1) (z + 1) (z + 0.5) : 2 z^{3} + 4 z^{2} + 2.5 z + 0.5

= \frac{1}{2 z ^{3} + 4 z ^{2} + 2.5 z + 0.5}

\frac{4}{( 3 x - 1 ) ^{2}}

\frac{( 4 x ^{3} - 5 x ) ^{8}}{8}

\frac{( x - 2 ) ( x - 3 )}{2 ( x + 3 )}

A (- 1, 3) B (2, - 3)

e^{x} (x - 1) + x^{2}

What is expand 1/((2z+1)(z+1)(z+0.5)) ?
The solution to expand 1/((2z+1)(z+1)(z+0.5)) is 1/(2z^3+4z^2+2.5z+0.5)