What is expand (x+2)(x-2)(x+δx+2)(x+δx-2) ?

The solution to expand (x+2)(x-2)(x+δx+2)(x+δx-2) is δ^2x^4+2δx^4+x^4-4δ^2x^2-8δx^2-8x^2+16

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expand (x+2)(x-2)(x+δx+2)(x+δx-2)

expand

(x + 2) (x - 2) (x + δ x + 2) (x + δ x - 2)

δ^{2} x^{4} + 2 δ x^{4} + x^{4} - 4 δ^{2} x^{2} - 8 δ x^{2} - 8 x^{2} + 16

Solution steps

(x + 2) (x - 2) (x + δ x + 2) (x + δ x - 2)

Expand

(x + 2) (x - 2) : x^{2} - 4

= (x^{2} - 4) (x + δ x + 2) (x + δ x - 2)

Expand

(x^{2} - 4) (x + δ x + 2) : x^{3} + δ x^{3} + 2 x^{2} - 4 x - 4 δ x - 8

= (x^{3} + δ x^{3} + 2 x^{2} - 4 x - 4 δ x - 8) (x + δ x - 2)

Expand

(x^{3} + δ x^{3} + 2 x^{2} - 4 x - 4 δ x - 8) (x + δ x - 2) : δ^{2} x^{4} + 2 δ x^{4} + x^{4} - 4 δ^{2} x^{2} - 8 δ x^{2} - 8 x^{2} + 16

= δ^{2} x^{4} + 2 δ x^{4} + x^{4} - 4 δ^{2} x^{2} - 8 δ x^{2} - 8 x^{2} + 16

(1 - x^{3} + x^{6})^{6}

\frac{7.5754}{s ( s + 3.8 ) + 7.5754}

\frac{8 x + 55}{( x + 9 ) ( x - 8 )}

x (3 + Δ y, 4) - x (3, 4)

R (1, - 1) y E (3, 4)

What is expand (x+2)(x-2)(x+δx+2)(x+δx-2) ?
The solution to expand (x+2)(x-2)(x+δx+2)(x+δx-2) is δ^2x^4+2δx^4+x^4-4δ^2x^2-8δx^2-8x^2+16