What is expand ((2-m)^2(-1+m))/3 ?

The solution to expand ((2-m)^2(-1+m))/3 is -4/3+(8m)/3-(5m^2)/3+(m^3)/3

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expand ((2-m)^2(-1+m))/3

expand

\frac{( 2 - m ) ^{2} ( - 1 + m )}{3}

- \frac{4}{3} + \frac{8 m}{3} - \frac{5 m ^{2}}{3} + \frac{m ^{3}}{3}

Solution steps

\frac{( 2 - m ) ^{2} ( - 1 + m )}{3}

(2 - m)^{2} = 4 - 4 m + m^{2}

= \frac{( m ^{2} - 4 m + 4 ) ( m - 1 )}{3}

Expand

(4 - 4 m + m^{2}) (- 1 + m) : - 4 + 8 m - 5 m^{2} + m^{3}

= \frac{- 4 + 8 m - 5 m ^{2} + m ^{3}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 4 + 8 m - 5 m ^{2} + m ^{3}}{3} = - \frac{4}{3} + \frac{8 m}{3} - \frac{5 m ^{2}}{3} + \frac{m ^{3}}{3}

= - \frac{4}{3} + \frac{8 m}{3} - \frac{5 m ^{2}}{3} + \frac{m ^{3}}{3}

\frac{5 ( 13 + 71 )}{49}

π (r^{2} x - \frac{1}{3} - x^{3})

0.8 (- y^{2} + 40 y - 391)^{2}

, (4 + 11)

(0.25 n^{3} + 4) (1, 5 n^{3} - 3)

What is expand ((2-m)^2(-1+m))/3 ?
The solution to expand ((2-m)^2(-1+m))/3 is -4/3+(8m)/3-(5m^2)/3+(m^3)/3