What is expand 1/((z+2)^2(z-3)) ?

The solution to expand 1/((z+2)^2(z-3)) is 1/(z^3+z^2-8z-12)

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expand 1/((z+2)^2(z-3))

expand

\frac{1}{( z + 2 ) ^{2} ( z - 3 )}

\frac{1}{z ^{3} + z ^{2} - 8 z - 12}

Solution steps

\frac{1}{( z + 2 ) ^{2} ( z - 3 )}

(z + 2)^{2} = z^{2} + 4 z + 4

= \frac{1}{( z ^{2} + 4 z + 4 ) ( z - 3 )}

Expand

(z^{2} + 4 z + 4) (z - 3) : z^{3} + z^{2} - 8 z - 12

= \frac{1}{z ^{3} + z ^{2} - 8 z - 12}

D C + (CB + A B^{^{'}}) B

2 x - 5 x + 2 y + x - y

\frac{( x - 2 ) ( x + 2 )}{x - a}

\frac{x + 1}{x ( x - 1 )}

\frac{1}{( 1 - x ) ( B - x )}

What is expand 1/((z+2)^2(z-3)) ?
The solution to expand 1/((z+2)^2(z-3)) is 1/(z^3+z^2-8z-12)