What is expand (3+2i)*[6+3i,0+0i,5+1i,4] ?

The solution to expand (3+2i)*[6+3i,0+0i,5+1i,4] is 3[6+3*0i,+0*5i,+1*4i,]+2i[6+3*0i,+0*5i,+1*4i,]

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expand (3+2i)*[6+3i,0+0i,5+1i,4]

expand

(3 + 2 i) \cdot [6 + 3 i, 0 + 0 i, 5 + 1 i, 4]

3 [6 + 3 \cdot 0 i, + 0 \cdot 5 i, + 1 \cdot 4 i,] + 2 i [6 + 3 \cdot 0 i, + 0 \cdot 5 i, + 1 \cdot 4 i,]

Solution steps

(3 + 2 i) [6 + 3 i, 0 + 0 i, 5 + 1 i, 4]

= (3 + 2 i) [6 + 3 \cdot 0 i, + 0 \cdot 5 i, + 1 \cdot 4 i,]

Apply the distributive law:

a (b + c) = ab + a c

a = [6 + 3 i, 0 + 0 i, 5 + 1 i, 4], b = 3, c = 2 i

= [6 + 3 i, 0 + 0 i, 5 + 1 i, 4] \cdot 3 + [6 + 3 i, 0 + 0 i, 5 + 1 i, 4] \cdot 2 i

= 3 [6 + 3 \cdot 0 i, + 0 \cdot 5 i, + 1 \cdot 4 i,] + 2 i [6 + 3 \cdot 0 i, + 0 \cdot 5 i, + 1 \cdot 4 i,]

lo g_{8} (27)

\frac{s + 2}{( s + 1 ) ( s + 3 )}

\frac{( a + h ) + 8}{- 3 ( a + h ) + 5}

\frac{( 12 + a ) 13}{2}

\frac{4 ( x - 2 )}{x - 3}

What is expand (3+2i)*[6+3i,0+0i,5+1i,4] ?
The solution to expand (3+2i)*[6+3i,0+0i,5+1i,4] is 3[6+3*0i,+0*5i,+1*4i,]+2i[6+3*0i,+0*5i,+1*4i,]