What is expand yQ_{0}(1-e^{-y/a}) ?

The solution to expand yQ_{0}(1-e^{-y/a}) is yQ_{0}-e^{-y/a}yQ_{0}

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expand yQ_{0}(1-e^{-y/a})

expand

y Q_{0} (1 - e^{- \frac{y}{a}})

y Q_{0} - e^{- \frac{y}{a}} y Q_{0}

Solution steps

y Q_{0} (1 - e^{- \frac{y}{a}})

Apply the distributive law:

a (b - c) = ab - a c

a = y Q_{0}, b = 1, c = e^{- \frac{y}{a}}

= y Q_{0} \cdot 1 - y Q_{0} e^{- \frac{y}{a}}

= 1 \cdot y Q_{0} - e^{- \frac{y}{a}} y Q_{0}

Multiply:

1 \cdot y = y

= y Q_{0} - e^{- \frac{y}{a}} y Q_{0}

\frac{2 ( n + 1 ) ( 2 n + 1 )}{n}

(2^{4}) (2^{3})

\frac{x - 1}{( x + 1 ) ( x + 2 )}

\frac{1}{( n + 2 ) ( 2 n + 2 )}

2 (8 - 3 e)

What is expand yQ_{0}(1-e^{-y/a}) ?
The solution to expand yQ_{0}(1-e^{-y/a}) is yQ_{0}-e^{-y/a}yQ_{0}