What are the solutions to the equation (2x+9)^2-1=0 ?

The solutions to the equation (2x+9)^2-1=0 are x=-4,x=-5

Find the zeros of (2x+9)^2-1=0

The zeros of (2x+9)^2-1=0 are x=-4,x=-5

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(2 x + 9)^{2} - 1 = 0

x = - 4, x = - 5

Solution steps

(2 x + 9)^{2} - 1 = 0

Move

1

to the right side

(2 x + 9)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 9 = 1 : x = - 4

Solve

2 x + 9 = - 1 : x = - 5

The solutions to the quadratic equation are:

x = - 4, x = - 5

x d y - y d x - x^{2} - y^{2} d x

x + 3 + 3

ln (4 - 3 e^{4 v - 2 x y})

∣ z + 3 ∣ \leq 2 z - 7

4.7 x = 2.5 x + 8.8

What are the solutions to the equation (2x+9)^2-1=0 ?
The solutions to the equation (2x+9)^2-1=0 are x=-4,x=-5
Find the zeros of (2x+9)^2-1=0
The zeros of (2x+9)^2-1=0 are x=-4,x=-5