What is expand (((3y-3))/2)^2 ?

The solution to expand (((3y-3))/2)^2 is (9y^2)/4-(9y)/2+9/4

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expand (((3y-3))/2)^2

expand

(\frac{( 3 y - 3 )}{2})^{2}

\frac{9 y ^{2}}{4} - \frac{9 y}{2} + \frac{9}{4}

Solution steps

(\frac{3 y - 3}{2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 3 y - 3 ) ^{2}}{2 ^{2}}

(3 y - 3)^{2} = 9 y^{2} - 18 y + 9

= \frac{9 y ^{2} - 18 y + 9}{2 ^{2}}

2^{2} = 4

= \frac{9 y ^{2} - 18 y + 9}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 y ^{2} - 18 y + 9}{4} = \frac{9 y ^{2}}{4} - \frac{18 y}{4} + \frac{9}{4}

= \frac{9 y ^{2}}{4} - \frac{18 y}{4} + \frac{9}{4}

Cancel

\frac{18 y}{4} : \frac{9 y}{2}

= \frac{9 y ^{2}}{4} - \frac{9 y}{2} + \frac{9}{4}

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What is expand (((3y-3))/2)^2 ?
The solution to expand (((3y-3))/2)^2 is (9y^2)/4-(9y)/2+9/4