What is expand-e^3x(12sin(2x)-5cos(2x)) ?

The solution to expand-e^3x(12sin(2x)-5cos(2x)) is -12e^3xsin(2x)+5e^3xcos(2x)

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expand-e^3x(12sin(2x)-5cos(2x))

expand

- e^{3} x (12 sin (2 x) - 5 cos (2 x))

- 12 e^{3} x sin (2 x) + 5 e^{3} x cos (2 x)

Solution steps

- e^{3} x (12 sin (2 x) - 5 cos (2 x))

Apply the distributive law:

a (b - c) = ab - a c

a = - e^{3} x, b = 12 sin (2 x), c = 5 cos (2 x)

= - e^{3} x \cdot 12 sin (2 x) - (- e^{3} x) \cdot 5 cos (2 x)

Apply minus-plus rules

- (- a) = a

= - 12 e^{3} x sin (2 x) + 5 e^{3} x cos (2 x)

\frac{i ( x - i y ) ^{2}}{( x + i y ) ^{2}}

90 (1 - e^{- \frac{t}{2}})

(3 e - 9) \cdot 8

\frac{2}{( x + a ) ( x + b )}

\frac{( x - 2 )}{( x - 1 ) ^{2}}

What is expand-e^3x(12sin(2x)-5cos(2x)) ?
The solution to expand-e^3x(12sin(2x)-5cos(2x)) is -12e^3xsin(2x)+5e^3xcos(2x)