What is expand-3/((s^2-4s)(s+1)) ?

The solution to expand-3/((s^2-4s)(s+1)) is -3/(s^3-3s^2-4s)

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expand-3/((s^2-4s)(s+1))

expand

- \frac{3}{( s ^{2} - 4 s ) ( s + 1 )}

- \frac{3}{s ^{3} - 3 s ^{2} - 4 s}

Solution steps

- \frac{3}{( s ^{2} - 4 s ) ( s + 1 )}

Expand

(s^{2} - 4 s) (s + 1) : s^{3} - 3 s^{2} - 4 s

= - \frac{3}{s ^{3} - 3 s ^{2} - 4 s}

5 \cdot 89

\frac{1 - v}{( 1 + v ) ( 1 - 2 v )}

\frac{1}{( 1 - x ) ( y - x ) ( z - x )}

e^{(x - s i n (x))^{2}}

(- 2, - 1) y (- 1, 2)

What is expand-3/((s^2-4s)(s+1)) ?
The solution to expand-3/((s^2-4s)(s+1)) is -3/(s^3-3s^2-4s)