What is expand ((-y+2)^3)/3 ?

The solution to expand ((-y+2)^3)/3 is -(y^3)/3+2y^2-4y+8/3

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expand ((-y+2)^3)/3

expand

\frac{( - y + 2 ) ^{3}}{3}

- \frac{y ^{3}}{3} + 2 y^{2} - 4 y + \frac{8}{3}

Solution steps

\frac{( - y + 2 ) ^{3}}{3}

(- y + 2)^{3} = - y^{3} + 6 y^{2} - 12 y + 8

= \frac{( - y ^{3} + 6 y ^{2} - 12 y + 8 )}{3}

Remove parentheses:

(- a) = - a

= \frac{- y ^{3} + 6 y ^{2} - 12 y + 8}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- y ^{3} + 6 y ^{2} - 12 y + 8}{3} = - \frac{y ^{3}}{3} + \frac{6 y ^{2}}{3} - \frac{12 y}{3} + \frac{8}{3}

= - \frac{y ^{3}}{3} + \frac{6 y ^{2}}{3} - \frac{12 y}{3} + \frac{8}{3}

Divide the numbers:

\frac{6}{3} = 2

= - \frac{y ^{3}}{3} + 2 y^{2} - \frac{12 y}{3} + \frac{8}{3}

Divide the numbers:

\frac{12}{3} = 4

= - \frac{y ^{3}}{3} + 2 y^{2} - 4 y + \frac{8}{3}

6 (3 k + 5 = 39)

\frac{( 6 2 - 3 ) ( 3 )}{2}

2 (0, 1 + x) - 8 (- x - 0.3)

9 \cdot 499

2 (x - 5) + 4 (x - 1 = 0)

What is expand ((-y+2)^3)/3 ?
The solution to expand ((-y+2)^3)/3 is -(y^3)/3+2y^2-4y+8/3