What is expand ((3r-1)(4r-1))/(12) ?

The solution to expand ((3r-1)(4r-1))/(12) is r^2-(7r)/(12)+1/12

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expand ((3r-1)(4r-1))/(12)

expand

\frac{( 3 r - 1 ) ( 4 r - 1 )}{12}

r^{2} - \frac{7 r}{12} + \frac{1}{12}

Solution steps

\frac{( 3 r - 1 ) ( 4 r - 1 )}{12}

Expand

(3 r - 1) (4 r - 1) : 12 r^{2} - 7 r + 1

= \frac{12 r ^{2} - 7 r + 1}{12}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{12 r ^{2} - 7 r + 1}{12} = \frac{12 r ^{2}}{12} - \frac{7 r}{12} + \frac{1}{12}

= \frac{12 r ^{2}}{12} - \frac{7 r}{12} + \frac{1}{12}

Divide the numbers:

\frac{12}{12} = 1

= r^{2} - \frac{7 r}{12} + \frac{1}{12}

\frac{1}{( n + 3 ) ( n + 4 )}

- \frac{4 ( 3 y + x )}{y ( 2 x - 3 y )}

\frac{4}{s ( s + 2 )}

(3 \cdot + 2 y) (\cdot + 3 y)

(x - 1) \cdot e^{2 x}

What is expand ((3r-1)(4r-1))/(12) ?
The solution to expand ((3r-1)(4r-1))/(12) is r^2-(7r)/(12)+1/12