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Popular >

expand (2y^3-2y)3^'

Solution

expand

(2 y^{3} - 2 y) 3^{^{'}}

Solution

2 \cdot 3^{'} y^{3} - 2 \cdot 3^{'} y

Solution steps

(2 y^{3} - 2 y) \cdot 3^{^{'}}

= 3^{^{^{'}}} (2 y^{3} - 2 y)

Apply the distributive law:

a (b - c) = ab - a c

a = 3^{^{'}}, b = 2 y^{3}, c = 2 y

= 3^{^{^{'}}} \cdot 2 y^{3} - 3^{^{^{'}}} \cdot 2 y

= 2 \cdot 3^{^{^{'}}} y^{3} - 2 \cdot 3^{^{^{'}}} y

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Frequently Asked Questions (FAQ)

What is expand (2y^3-2y)3^' ?
The solution to expand (2y^3-2y)3^' is 2*3^'y^3-2*3^'y