What are the solutions to the equation x^2-6x=20 ?

The solutions to the equation x^2-6x=20 are x=3+sqrt(29),x=3-sqrt(29)

Find the zeros of x^2-6x=20

The zeros of x^2-6x=20 are x=3+sqrt(29),x=3-sqrt(29)

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x^{2} - 6 x = 20

x = 3 + 29, x = 3 - 29

Solution steps

x^{2} - 6 x = 20

Move

20

to the left side

x^{2} - 6 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 20) = 229

x_{1, 2} = \frac{- ( - 6 ) \pm 2 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 29}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 29}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 29}{2 \cdot 1} : 3 + 29

x = \frac{- ( - 6 ) - 2 29}{2 \cdot 1} : 3 - 29

The solutions to the quadratic equation are:

x = 3 + 29, x = 3 - 29

\frac{1}{2} \cdot \frac{2}{3}

x^{2} = \frac{36}{49}

9 (x + 10) + 5 = 113

e^{- \frac{iπ}{2}}

3 x - 12 = 0

What are the solutions to the equation x^2-6x=20 ?
The solutions to the equation x^2-6x=20 are x=3+sqrt(29),x=3-sqrt(29)
Find the zeros of x^2-6x=20
The zeros of x^2-6x=20 are x=3+sqrt(29),x=3-sqrt(29)