What is expand ((x^3-6x)^2)/6 ?

The solution to expand ((x^3-6x)^2)/6 is (x^6)/6-2x^4+6x^2

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expand ((x^3-6x)^2)/6

expand

\frac{( x ^{3} - 6 x ) ^{2}}{6}

\frac{x ^{6}}{6} - 2 x^{4} + 6 x^{2}

Solution steps

\frac{( x ^{3} - 6 x ) ^{2}}{6}

(x^{3} - 6 x)^{2} = x^{6} - 12 x^{4} + 36 x^{2}

= \frac{x ^{6} - 12 x ^{4} + 36 x ^{2}}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{6} - 12 x ^{4} + 36 x ^{2}}{6} = \frac{x ^{6}}{6} - \frac{12 x ^{4}}{6} + \frac{36 x ^{2}}{6}

= \frac{x ^{6}}{6} - \frac{12 x ^{4}}{6} + \frac{36 x ^{2}}{6}

Divide the numbers:

\frac{12}{6} = 2

= \frac{x ^{6}}{6} - 2 x^{4} + \frac{36 x ^{2}}{6}

Divide the numbers:

\frac{36}{6} = 6

= \frac{x ^{6}}{6} - 2 x^{4} + 6 x^{2}

(2 x y - sec^{2} (x)) d x

\frac{4}{( s - 3 ) ( s ^{2} + 9 )}

\frac{2 ( - x ^{2} - 1 )}{( x ^{2} - 1 )}

\frac{7 ( y - 4 )}{6 ( y + 4 )}

(6 x y) d x + (4 y + 9 x^{2}) d y

What is expand ((x^3-6x)^2)/6 ?
The solution to expand ((x^3-6x)^2)/6 is (x^6)/6-2x^4+6x^2