What is expand 3(-2e^{-2x}+3x^2-2x-3) ?

The solution to expand 3(-2e^{-2x}+3x^2-2x-3) is -6e^{-2x}+9x^2-6x-9

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expand 3(-2e^{-2x}+3x^2-2x-3)

expand

3 (- 2 e^{- 2 x} + 3 x^{2} - 2 x - 3)

- 6 e^{- 2 x} + 9 x^{2} - 6 x - 9

Solution steps

3 (- 2 e^{- 2 x} + 3 x^{2} - 2 x - 3)

Distribute parentheses

= 3 (- 2 e^{- 2 x}) + 3 \cdot 3 x^{2} + 3 (- 2 x) + 3 (- 3)

Apply minus-plus rules

+ (- a) = - a

= - 3 \cdot 2 e^{- 2 x} + 3 \cdot 3 x^{2} - 3 \cdot 2 x - 3 \cdot 3

Simplify

- 3 \cdot 2 e^{- 2 x} + 3 \cdot 3 x^{2} - 3 \cdot 2 x - 3 \cdot 3 : - 6 e^{- 2 x} + 9 x^{2} - 6 x - 9

= - 6 e^{- 2 x} + 9 x^{2} - 6 x - 9

3 sin (2 (x - \frac{π}{4}))

\frac{1}{- 2 ( x + h ) - 3}

(A e^{- k x} + A e^{k x})^{2}

1 - x^{2} + (π - arccos (x)) x

(x - 2) (x - 1)^{'}

What is expand 3(-2e^{-2x}+3x^2-2x-3) ?
The solution to expand 3(-2e^{-2x}+3x^2-2x-3) is -6e^{-2x}+9x^2-6x-9