What is expand-1/((ba-a)(a+ab)) ?

The solution to expand-1/((ba-a)(a+ab)) is -1/(b^2a^2-a^2)

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expand-1/((ba-a)(a+ab))

expand

- \frac{1}{( ba - a ) ( a + ab )}

- \frac{1}{b ^{2} a ^{2} - a ^{2}}

Solution steps

- \frac{1}{( ba - a ) ( a + ab )}

Expand

(ba - a) (a + ab) : b^{2} a^{2} - a^{2}

= - \frac{1}{b ^{2} a ^{2} - a ^{2}}

sin (π (x + h))

(1 + x) \frac{d y}{d x}

sin (x (t - 2))

\frac{( 1 + y ) ^{3}}{3}

\frac{1}{( x ^{2} - 10 x + 35 ) ^{3}}

What is expand-1/((ba-a)(a+ab)) ?
The solution to expand-1/((ba-a)(a+ab)) is -1/(b^2a^2-a^2)