What is expand (1-x)/(x(x+1)(x-2)(x+2)) ?

The solution to expand (1-x)/(x(x+1)(x-2)(x+2)) is (1-x)/(x^4-4x^2+x^3-4x)

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expand (1-x)/(x(x+1)(x-2)(x+2))

expand

\frac{1 - x}{x ( x + 1 ) ( x - 2 ) ( x + 2 )}

\frac{1 - x}{x ^{4} - 4 x ^{2} + x ^{3} - 4 x}

Solution steps

\frac{1 - x}{x ( x + 1 ) ( x - 2 ) ( x + 2 )}

Expand

x (x + 1) (x - 2) (x + 2) : x^{4} - 4 x^{2} + x^{3} - 4 x

= \frac{1 - x}{x ^{4} - 4 x ^{2} + x ^{3} - 4 x}

C (- 2, - 3)

\frac{x ^{2} + 3 ( x + 1 )}{7 x ( x + 1 )}

(a^{2})^{3}

10 (1 0^{2} - d^{2})

(a^{2})^{2}

What is expand (1-x)/(x(x+1)(x-2)(x+2)) ?
The solution to expand (1-x)/(x(x+1)(x-2)(x+2)) is (1-x)/(x^4-4x^2+x^3-4x)