What is expand (-1,5)y(3,-2) ?

The solution to expand (-1,5)y(3,-2) is 3(-1*5,)y,-2(-1*5,)y

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expand (-1,5)y(3,-2)

expand

(- 1, 5) y (3, - 2)

3 (- 1 \cdot 5,) y, - 2 (- 1 \cdot 5,) y

Solution steps

(- 1, 5) y (3, - 2)

= (- 1 \cdot 5,) (3, - 2) y

Apply the distributive law:

a (b - c) = ab - a c

a = (- 1, 5) y, b = 3,, c = 2

= (- 1, 5) y \cdot 3, - (- 1, 5) y \cdot 2

= 3 (- 1 \cdot 5,) y, - 2 (- 1 \cdot 5,) y

5 - 25 (5 + 2)

\frac{n + 1}{n ^{2} ( n + 2 ) ^{2}}

\frac{2 x - 1}{( x + 2 ) ( x - 1 )}

x (2 x e^{x} + e^{x} x^{2})

\frac{4 ( 4 - 2 )}{7}

What is expand (-1,5)y(3,-2) ?
The solution to expand (-1,5)y(3,-2) is 3(-1*5,)y,-2(-1*5,)y