What is expand e^x(-1-e^{2x}) ?

The solution to expand e^x(-1-e^{2x}) is -e^x-e^{3x}

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expand e^x(-1-e^{2x})

expand

e^{x} (- 1 - e^{2 x})

- e^{x} - e^{3 x}

Solution steps

e^{x} (- 1 - e^{2 x})

Apply the distributive law:

a (b - c) = ab - a c

a = e^{x}, b = - 1, c = e^{2 x}

= e^{x} (- 1) - e^{x} e^{2 x}

Apply minus-plus rules

+ (- a) = - a

= - 1 \cdot e^{x} - e^{x} e^{2 x}

Simplify

- 1 \cdot e^{x} - e^{x} e^{2 x} : - e^{x} - e^{3 x}

= - e^{x} - e^{3 x}

\frac{( b + k x ^{2} ) ( b - k x ^{2} )}{2}

- 2^{8}

- 5 \cdot (- 1)

\frac{2}{5 ( 2 x - 7 )}

\frac{7}{3 ( 2 x + 1 )}

What is expand e^x(-1-e^{2x}) ?
The solution to expand e^x(-1-e^{2x}) is -e^x-e^{3x}