What are the solutions to the equation 6z^2+6z=10z-6 ?

The solutions to the equation 6z^2+6z=10z-6 are z= 1/3+i(2sqrt(2))/3 ,z= 1/3-i(2sqrt(2))/3

Find the zeros of 6z^2+6z=10z-6

The zeros of 6z^2+6z=10z-6 are z= 1/3+i(2sqrt(2))/3 ,z= 1/3-i(2sqrt(2))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 z^{2} + 6 z = 10 z - 6

z = \frac{1}{3} + i \frac{2 2}{3}, z = \frac{1}{3} - i \frac{2 2}{3}

Solution steps

6 z^{2} + 6 z = 10 z - 6

Move

6

to the left side

6 z^{2} + 6 z + 6 = 10 z

Move

10 z

to the left side

6 z^{2} - 4 z + 6 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 6 \cdot 6}{2 \cdot 6}

Simplify

(- 4)^{2} - 4 \cdot 6 \cdot 6 : 82 i

z_{1, 2} = \frac{- ( - 4 ) \pm 8 2 i}{2 \cdot 6}

Separate the solutions

z_{1} = \frac{- ( - 4 ) + 8 2 i}{2 \cdot 6}, z_{2} = \frac{- ( - 4 ) - 8 2 i}{2 \cdot 6}

z = \frac{- ( - 4 ) + 8 2 i}{2 \cdot 6} : \frac{1}{3} + i \frac{2 2}{3}

z = \frac{- ( - 4 ) - 8 2 i}{2 \cdot 6} : \frac{1}{3} - i \frac{2 2}{3}

The solutions to the quadratic equation are:

z = \frac{1}{3} + i \frac{2 2}{3}, z = \frac{1}{3} - i \frac{2 2}{3}

7 x - 3 x - 8 = 24

14 x^{2} - 9 x - 18

\frac{2 - i}{4 + i}

x^{2} + 6 x + 14 = 0

- x^{2} + 10 x - 21 = 0

What are the solutions to the equation 6z^2+6z=10z-6 ?
The solutions to the equation 6z^2+6z=10z-6 are z= 1/3+i(2sqrt(2))/3 ,z= 1/3-i(2sqrt(2))/3
Find the zeros of 6z^2+6z=10z-6
The zeros of 6z^2+6z=10z-6 are z= 1/3+i(2sqrt(2))/3 ,z= 1/3-i(2sqrt(2))/3