What is expand ((n+1)(4n-1))/((4n+3)n) ?

The solution to expand ((n+1)(4n-1))/((4n+3)n) is (4n^2+3n-1)/(4n^2+3n)

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expand ((n+1)(4n-1))/((4n+3)n)

expand

\frac{( n + 1 ) ( 4 n - 1 )}{( 4 n + 3 ) n}

\frac{4 n ^{2} + 3 n - 1}{4 n ^{2} + 3 n}

Solution steps

\frac{( n + 1 ) ( 4 n - 1 )}{( 4 n + 3 ) n}

Expand

(4 n + 3) n : 4 n^{2} + 3 n

= \frac{( n + 1 ) ( 4 n - 1 )}{4 n ^{2} + 3 n}

Expand

(n + 1) (4 n - 1) : 4 n^{2} + 3 n - 1

= \frac{4 n ^{2} + 3 n - 1}{4 n ^{2} + 3 n}

\frac{1}{s ^{2} ( s ^{2} + 16 )}

(ln (y) = x - 2) e

(- 4 x) (8 x) - 1 - x^{2} - 4 x

\frac{x ^{2}}{( x - 2 ) ^{2} ( x + 3 )}

(y - x y) d x + x d y

What is expand ((n+1)(4n-1))/((4n+3)n) ?
The solution to expand ((n+1)(4n-1))/((4n+3)n) is (4n^2+3n-1)/(4n^2+3n)