What is expand e^{2x}(3e^{-x}+e^{3x}) ?

The solution to expand e^{2x}(3e^{-x}+e^{3x}) is 3e^x+e^{5x}

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expand e^{2x}(3e^{-x}+e^{3x})

expand

e^{2 x} (3 e^{- x} + e^{3 x})

3 e^{x} + e^{5 x}

Solution steps

e^{2 x} (3 e^{- x} + e^{3 x})

Apply the distributive law:

a (b + c) = ab + a c

a = e^{2 x}, b = 3 e^{- x}, c = e^{3 x}

= e^{2 x} \cdot 3 e^{- x} + e^{2 x} e^{3 x}

= 3 e^{2 x} e^{- x} + e^{2 x} e^{3 x}

Simplify

3 e^{2 x} e^{- x} + e^{2 x} e^{3 x} : 3 e^{x} + e^{5 x}

= 3 e^{x} + e^{5 x}

x (x + 4)^{2} d x

l m (w x) + (3 x + 1) ln (x)

\frac{x ( x - 9 )}{x - 81}

f^{'} (x) (2 x - 3)

(64)^{\frac{2}{3}}

What is expand e^{2x}(3e^{-x}+e^{3x}) ?
The solution to expand e^{2x}(3e^{-x}+e^{3x}) is 3e^x+e^{5x}