What is expand ((x-5)(x+1))/2 ?

The solution to expand ((x-5)(x+1))/2 is (x^2)/2-2x-5/2

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expand ((x-5)(x+1))/2

expand

\frac{( x - 5 ) ( x + 1 )}{2}

\frac{x ^{2}}{2} - 2 x - \frac{5}{2}

Solution steps

\frac{( x - 5 ) ( x + 1 )}{2}

Expand

(x - 5) (x + 1) : x^{2} - 4 x - 5

= \frac{x ^{2} - 4 x - 5}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 4 x - 5}{2} = \frac{x ^{2}}{2} - \frac{4 x}{2} - \frac{5}{2}

= \frac{x ^{2}}{2} - \frac{4 x}{2} - \frac{5}{2}

Divide the numbers:

\frac{4}{2} = 2

= \frac{x ^{2}}{2} - 2 x - \frac{5}{2}

n p \cdot (n p - p + 1)^{2}

\frac{- x + a}{( a + ab ) ( - ba + a )}

(6 x + 3 y = 1, 8) (x + y = 4)

(3 x^{2} - 14 x + 16) \circ (x - 5)

What is expand ((x-5)(x+1))/2 ?
The solution to expand ((x-5)(x+1))/2 is (x^2)/2-2x-5/2