What is expand 5n(49n+(-6)^{-1}=7n) ?

The solution to expand 5n(49n+(-6)^{-1}=7n) is 245n^2-(5n)/6 =7n

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expand 5n(49n+(-6)^{-1}=7n)

expand

5 n (49 n + (- 6)^{- 1} = 7 n)

245 n^{2} - \frac{5 n}{6} = 7 n

Solution steps

5 n (49 n + (- 6)^{- 1} = 7 n)

= 5 n (49 n + (- 6)^{- 1} \cdot 7 = n)

Apply the distributive law:

a (b + c) = ab + a c

a = 5 n, b = 49 n, c = (- 6)^{- 1} = 7 n

5 n \cdot 49 n + 5 n (- 6)^{- 1} = 7 n

5 \cdot 49 nn + (- 6)^{- 1} \cdot 5 n = 7 n

Expand

5 \cdot 49 nn + (- 6)^{- 1} \cdot 5 n : 245 n^{2} - \frac{5 n}{6}

245 n^{2} - \frac{5 n}{6} = 7 n

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What is expand 5n(49n+(-6)^{-1}=7n) ?
The solution to expand 5n(49n+(-6)^{-1}=7n) is 245n^2-(5n)/6 =7n