What is expand (2k-1)/(2k(2k+1)(2k+2)) ?

The solution to expand (2k-1)/(2k(2k+1)(2k+2)) is (2k-1)/(8k^3+12k^2+4k)

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expand (2k-1)/(2k(2k+1)(2k+2))

expand

\frac{2 k - 1}{2 k ( 2 k + 1 ) ( 2 k + 2 )}

\frac{2 k - 1}{8 k ^{3} + 12 k ^{2} + 4 k}

Solution steps

\frac{2 k - 1}{2 k ( 2 k + 1 ) ( 2 k + 2 )}

Expand

2 k (2 k + 1) (2 k + 2) : 8 k^{3} + 12 k^{2} + 4 k

= \frac{2 k - 1}{8 k ^{3} + 12 k ^{2} + 4 k}

(π - 4)^{2}

- \frac{6}{( x - 2 ) ^{2}}

(21 x - 6 y = 5, 4) - (9 + y = 3.5 x)

e^{(- 2 - j^{4} π) t}

x^{3} - 1^{3}

What is expand (2k-1)/(2k(2k+1)(2k+2)) ?
The solution to expand (2k-1)/(2k(2k+1)(2k+2)) is (2k-1)/(8k^3+12k^2+4k)