What is expand ((x+1)(2x+1))/6 ?

The solution to expand ((x+1)(2x+1))/6 is (x^2)/3+x/2+1/6

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expand ((x+1)(2x+1))/6

expand

\frac{( x + 1 ) ( 2 x + 1 )}{6}

\frac{x ^{2}}{3} + \frac{x}{2} + \frac{1}{6}

Solution steps

\frac{( x + 1 ) ( 2 x + 1 )}{6}

Expand

(x + 1) (2 x + 1) : 2 x^{2} + 3 x + 1

= \frac{2 x ^{2} + 3 x + 1}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{2} + 3 x + 1}{6} = \frac{2 x ^{2}}{6} + \frac{3 x}{6} + \frac{1}{6}

= \frac{2 x ^{2}}{6} + \frac{3 x}{6} + \frac{1}{6}

Cancel

\frac{2 x ^{2}}{6} : \frac{x ^{2}}{3}

= \frac{x ^{2}}{3} + \frac{3 x}{6} + \frac{1}{6}

Cancel

\frac{3 x}{6} : \frac{x}{2}

= \frac{x ^{2}}{3} + \frac{x}{2} + \frac{1}{6}

(5 cos (x) + 4 sin (x)) d x

\frac{( x - 2 ) ^{3}}{( x - 4 ) ^{4}}

(x^{2} + 3 x - 2) (ln (x))

(1 + 2 x - x^{2})^{6}

\frac{( - 5 ) x - 1}{5}

What is expand ((x+1)(2x+1))/6 ?
The solution to expand ((x+1)(2x+1))/6 is (x^2)/3+x/2+1/6