What are the solutions to the equation 0=s^2+2s+2 ?

The solutions to the equation 0=s^2+2s+2 are s=-1+i,s=-1-i

Find the zeros of 0=s^2+2s+2

The zeros of 0=s^2+2s+2 are s=-1+i,s=-1-i

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0 = s^{2} + 2 s + 2

s = - 1 + i, s = - 1 - i

Solution steps

0 = s^{2} + 2 s + 2

Switch sides

s^{2} + 2 s + 2 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 2 : 2 i

s_{1, 2} = \frac{- 2 \pm 2 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 2 i}{2 \cdot 1}, s_{2} = \frac{- 2 - 2 i}{2 \cdot 1}

s = \frac{- 2 + 2 i}{2 \cdot 1} : - 1 + i

s = \frac{- 2 - 2 i}{2 \cdot 1} : - 1 - i

The solutions to the quadratic equation are:

s = - 1 + i, s = - 1 - i

\frac{x}{6} + 12 = (- 12)

369

8 y^{2} - 200 z^{2}

5 x + 2 (x + 1) = 23

3 - 5

What are the solutions to the equation 0=s^2+2s+2 ?
The solutions to the equation 0=s^2+2s+2 are s=-1+i,s=-1-i
Find the zeros of 0=s^2+2s+2
The zeros of 0=s^2+2s+2 are s=-1+i,s=-1-i