What is expand ((z-1)(2z-1))/2 ?

The solution to expand ((z-1)(2z-1))/2 is z^2-(3z)/2+1/2

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expand ((z-1)(2z-1))/2

expand

\frac{( z - 1 ) ( 2 z - 1 )}{2}

z^{2} - \frac{3 z}{2} + \frac{1}{2}

Solution steps

\frac{( z - 1 ) ( 2 z - 1 )}{2}

Expand

(z - 1) (2 z - 1) : 2 z^{2} - 3 z + 1

= \frac{2 z ^{2} - 3 z + 1}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 z ^{2} - 3 z + 1}{2} = \frac{2 z ^{2}}{2} - \frac{3 z}{2} + \frac{1}{2}

= \frac{2 z ^{2}}{2} - \frac{3 z}{2} + \frac{1}{2}

Divide the numbers:

\frac{2}{2} = 1

= z^{2} - \frac{3 z}{2} + \frac{1}{2}

(3 x + 4 y = - 2, 3) (2 y - x = - 19)

\frac{k}{x ( x + 2 k )}

lo g_{2} (8)

f (x + d x)

1 5^{3} - 7^{3}

What is expand ((z-1)(2z-1))/2 ?
The solution to expand ((z-1)(2z-1))/2 is z^2-(3z)/2+1/2