What is expand-2(x+1)e^x ?

The solution to expand-2(x+1)e^x is -2e^xx-2e^x

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expand-2(x+1)e^x

expand

- 2 (x + 1) e^{x}

- 2 e^{x} x - 2 e^{x}

Solution steps

- 2 (x + 1) e^{x}

= - 2 e^{x} (x + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = - 2 e^{x}, b = x, c = 1

= - 2 e^{x} x + (- 2 e^{x}) \cdot 1

Apply minus-plus rules

+ (- a) = - a

= - 2 e^{x} x - 2 \cdot 1 \cdot e^{x}

Multiply the numbers:

2 \cdot 1 = 2

= - 2 e^{x} x - 2 e^{x}

\frac{( x + 3 ) ( x - 1 )}{( x + 1 )}

x (1 + Δ)^{2}

\frac{d}{d y} ((x) (x y + sin (x y) + x))

\frac{( 4 x - 3 ) ( x + 2 )}{8 x + 6}

1 (- 4 x + 2 y = 6)