What is expand ((2x-1))/((3x-1)(x-1)) ?

The solution to expand ((2x-1))/((3x-1)(x-1)) is (2x-1)/(3x^2-4x+1)

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expand ((2x-1))/((3x-1)(x-1))

expand

\frac{( 2 x - 1 )}{( 3 x - 1 ) ( x - 1 )}

\frac{2 x - 1}{3 x ^{2} - 4 x + 1}

Solution steps

\frac{2 x - 1}{( 3 x - 1 ) ( x - 1 )}

Expand

(3 x - 1) (x - 1) : 3 x^{2} - 4 x + 1

= \frac{2 x - 1}{3 x ^{2} - 4 x + 1}

\frac{5 ( 3 30 - 10 )}{34}

\frac{689}{96 ( 2 x - 1 )}

\frac{( x + 3 ) ( x - 6 )}{( x + 1 ) ( 2 x + 3 )}

\frac{6}{( x ^{2} - 4 ) ^{2}}

\frac{d}{d y} ((x (y)) (y - 1))

What is expand ((2x-1))/((3x-1)(x-1)) ?
The solution to expand ((2x-1))/((3x-1)(x-1)) is (2x-1)/(3x^2-4x+1)