What is expand (x-6)/(x(x-3)(x+1)) ?

The solution to expand (x-6)/(x(x-3)(x+1)) is (x-6)/(x^3-2x^2-3x)

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expand (x-6)/(x(x-3)(x+1))

expand

\frac{x - 6}{x ( x - 3 ) ( x + 1 )}

\frac{x - 6}{x ^{3} - 2 x ^{2} - 3 x}

Solution steps

\frac{x - 6}{x ( x - 3 ) ( x + 1 )}

Expand

x (x - 3) (x + 1) : x^{3} - 2 x^{2} - 3 x

= \frac{x - 6}{x ^{3} - 2 x ^{2} - 3 x}

L {cos (4 t)} (s + 2)

e^{2 (x + 5)}

\frac{1}{( ( 1 - x ) ( B - x ) ( D - x ) )}

(x - π)^{9}

x y d x - (x^{2} + 2 y^{2}) d y

What is expand (x-6)/(x(x-3)(x+1)) ?
The solution to expand (x-6)/(x(x-3)(x+1)) is (x-6)/(x^3-2x^2-3x)