What is expand 2e^3f(2e-3ef^2+f^3) ?

The solution to expand 2e^3f(2e-3ef^2+f^3) is 2e^3f^4-6e^4f^3+4e^4f

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expand 2e^3f(2e-3ef^2+f^3)

expand

2 e^{3} f (2 e - 3 e f^{2} + f^{3})

2 e^{3} f^{4} - 6 e^{4} f^{3} + 4 e^{4} f

Solution steps

2 e^{3} f (2 e - 3 e f^{2} + f^{3})

Distribute parentheses

= 2 e^{3} f \cdot 2 e + 2 e^{3} f (- 3 e f^{2}) + 2 e^{3} f f^{3}

Apply minus-plus rules

+ (- a) = - a

= 2 \cdot 2 e^{3} e f - 2 \cdot 3 e^{3} e f^{2} f + 2 e^{3} f^{3} f

Simplify

2 \cdot 2 e^{3} e f - 2 \cdot 3 e^{3} e f^{2} f + 2 e^{3} f^{3} f : 2 e^{3} f^{4} - 6 e^{4} f^{3} + 4 e^{4} f

= 2 e^{3} f^{4} - 6 e^{4} f^{3} + 4 e^{4} f

(b + d^{2}) a

8 (x + 2)^{2} + y^{2}

f (\frac{x}{4} - \frac{4}{x}) d x

\frac{( x - 12 ) ( x + 13 )}{x ^{2} - 1}

\frac{( 4 y + x ) ^{3}}{8}

What is expand 2e^3f(2e-3ef^2+f^3) ?
The solution to expand 2e^3f(2e-3ef^2+f^3) is 2e^3f^4-6e^4f^3+4e^4f