What is expand x(-e^{-x+4}+1=0.9) ?

The solution to expand x(-e^{-x+4}+1=0.9) is -e^{-x+4}x+x=0.9

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expand x(-e^{-x+4}+1=0.9)

expand

x (- e^{- x + 4} + 1 = 0.9)

- e^{- x + 4} x + x = 0.9

Solution steps

x (- e^{- x + 4} + 1 = 0.9)

= x (- e^{- x + 4} + 1 \cdot 0.9 =)

Apply the distributive law:

a (b + c) = ab + a c

a = x, b = - e^{- x + 4}, c = 1 = 0.9

x (- e^{- x + 4}) + x \cdot 1 = 0.9

Apply minus-plus rules

+ (- a) = - a

- e^{- x + 4} x + 1 \cdot x = 0.9

Expand

- e^{- x + 4} x + 1 \cdot x : - e^{- x + 4} x + x

- e^{- x + 4} x + x = 0.9

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What is expand x(-e^{-x+4}+1=0.9) ?
The solution to expand x(-e^{-x+4}+1=0.9) is -e^{-x+4}x+x=0.9