What is expand cos(2t)[h(t-pi/2)] ?

The solution to expand cos(2t)[h(t-pi/2)] is thcos(2t)-(pihcos(2t))/2

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expand cos(2t)[h(t-pi/2)]

expand

cos (2 t) [h (t - \frac{π}{2})]

t h cos (2 t) - \frac{πh cos ( 2 t )}{2}

Solution steps

cos (2 t) (h (t - \frac{π}{2}))

Remove parentheses:

(a) = a

= cos (2 t) h (t - \frac{π}{2})

= h cos (2 t) (t - \frac{π}{2})

Apply the distributive law:

a (b - c) = ab - a c

a = cos (2 t) h, b = t, c = \frac{π}{2}

= cos (2 t) h t - cos (2 t) h \frac{π}{2}

= t h cos (2 t) - \frac{π}{2} h cos (2 t)

\frac{π}{2} h cos (2 t) = \frac{πh cos ( 2 t )}{2}

= t h cos (2 t) - \frac{πh cos ( 2 t )}{2}

2 x y d x + (x^{2} - y) d y

- \frac{x + 1}{x ^{2} ( x + 4 ) ^{2}}

(200 - e) \cdot 50

\frac{9}{( x + 1 ) ^{2}}

\frac{c x + k}{( x - p ) ^{2}}

What is expand cos(2t)[h(t-pi/2)] ?
The solution to expand cos(2t)[h(t-pi/2)] is thcos(2t)-(pihcos(2t))/2