What is expand (2x^3+2)(2x^3-5)' ?

The solution to expand (2x^3+2)(2x^3-5)' is 2x^3(2x^3-5)'+2(2x^3-5)'

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expand (2x^3+2)(2x^3-5)'

expand

(2 x^{3} + 2) (2 x^{3} - 5)^{'}

2 x^{3} (2 x^{3} - 5)' + 2 (2 x^{3} - 5)'

Solution steps

(2 x^{3} + 2) (2 x^{3} - 5)^{'}

Apply the distributive law:

a (b + c) = ab + a c

a = (2 x^{3} - 5)^{'}, b = 2 x^{3}, c = 2

= (2 x^{3} - 5)^{^{'}} 2 x^{3} + (2 x^{3} - 5)^{^{'}} 2

= 2 x^{3} (2 x^{3} - 5)^{^{'}} + 2 (2 x^{3} - 5)^{^{'}}

\frac{4 x + 14}{( x + 5 ) ( x - 1 )}

(a + b c) + (d e + f) (a + b)

x - 3 (x^{2} (x^{3} + 8))

- \frac{2 ( 2 x - 3 )}{x - 3}

d y ((\frac{1}{1 - y}) - 1)

What is expand (2x^3+2)(2x^3-5)' ?
The solution to expand (2x^3+2)(2x^3-5)' is 2x^3(2x^3-5)'+2(2x^3-5)'