What is expand ((2x-1)^2)/(2(x-1)) ?

The solution to expand ((2x-1)^2)/(2(x-1)) is (4x^2-4x+1)/(2x-2)

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expand ((2x-1)^2)/(2(x-1))

expand

\frac{( 2 x - 1 ) ^{2}}{2 ( x - 1 )}

\frac{4 x ^{2} - 4 x + 1}{2 x - 2}

Solution steps

\frac{( 2 x - 1 ) ^{2}}{2 ( x - 1 )}

(2 x - 1)^{2} = 4 x^{2} - 4 x + 1

= \frac{4 x ^{2} - 4 x + 1}{2 ( x - 1 )}

Expand

2 (x - 1) : 2 x - 2

= \frac{4 x ^{2} - 4 x + 1}{2 x - 2}

4 cos (2 (x - \frac{π}{3})) + 1

(1 - u - v, 1 - u, u) \cdot (1, 1, 1)

(r^{2} - 4 r - 5) \cdot e^{r x}

2 (C e^{- 2 x} + \frac{1}{3} e^{x})

(x - z)^{6}

What is expand ((2x-1)^2)/(2(x-1)) ?
The solution to expand ((2x-1)^2)/(2(x-1)) is (4x^2-4x+1)/(2x-2)