expand (4t^2-t-3=0-7+7i)(-2+5i)

الحلّ

expand

(4 t^{2} - t - 3 = 0 - 7 + 7 i) (- 2 + 5 i)

(- 8 t^{2} + 2 t + 3) + i = 20 t^{2} - i = 5 t - 21 - 49 i

خطوات الحلّ

(4 t^{2} - t - 3 = 0 - 7 + 7 i) (- 2 + 5 i)

= (- 2 + 5 i) (4 t^{2} - t - 3 \cdot 0 = - 7 + 7 i)

(4 t^{2} - t - 3 = 0 - 7 + 7 i) (- 2 + 5 i)

وسٌع:

(- 8 t^{2} + 2 t + 3) + i (20 t^{2} - 5 t) = - 21 - 49 i

(- 8 t^{2} + 2 t + 3) + i (20 t^{2} - 5 t) = - 21 - 49 i

i = (20 t^{2} - 5 t)

وسٌع:

i = 20 t^{2} - i = 5 t

(- 8 t^{2} + 2 t + 3) + i = 20 t^{2} - i = 5 t - 21 - 49 i

\frac{2 x + 5}{x ( x + 5 )}

x^{3} δ (x - 4)

in (1 + e^{x})

(6 x + 12 y = 3, 6) (4 x - 6 y = - 4)

x^{n} (1.5 + e^{- 2 x + 8})