What is expand sqrt(x^4+4x+9)(x^3+1)dx ?

The solution to expand sqrt(x^4+4x+9)(x^3+1)dx is x^3dxsqrt(x^4+4x+9)+dxsqrt(x^4+4x+9)

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expand sqrt(x^4+4x+9)(x^3+1)dx

expand

x^{4} + 4 x + 9 (x^{3} + 1) d x

x^{3} d x x^{4} + 4 x + 9 + d x x^{4} + 4 x + 9

Solution steps

x^{4} + 4 x + 9 (x^{3} + 1) d x

= (x^{3} + 1) d x x^{4} + 4 x + 9

Apply the distributive law:

a (b + c) = ab + a c

a = x^{4} + 4 x + 9 d x, b = x^{3}, c = 1

= x^{4} + 4 x + 9 d x x^{3} + x^{4} + 4 x + 9 d x \cdot 1

= x^{3} d x x^{4} + 4 x + 9 + 1 \cdot d x x^{4} + 4 x + 9

Multiply:

1 \cdot d x = d x

= x^{3} d x x^{4} + 4 x + 9 + d x x^{4} + 4 x + 9

(2 + π)^{2}

(X - 1) (e^{X} - e)

\frac{3 e ^{- 3 s}}{s ( s ^{2} + 1 )}

\frac{n ( n + 1 ) + 1}{x ^{2}}

sin (πn (2 k + 1))

What is expand sqrt(x^4+4x+9)(x^3+1)dx ?
The solution to expand sqrt(x^4+4x+9)(x^3+1)dx is x^3dxsqrt(x^4+4x+9)+dxsqrt(x^4+4x+9)