What is expand-(6x-(4x+8)=9+(6x+3)) ?

The solution to expand-(6x-(4x+8)=9+(6x+3)) is -6x+=72-6x-3

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expand-(6x-(4x+8)=9+(6x+3))

expand

- (6 x - (4 x + 8) = 9 + (6 x + 3))

- 6 x + = 72 - 6 x - 3

Solution steps

- (6 x - (4 x + 8) = 9 + (6 x + 3))

= - (6 x - 9 = (4 x + 8) + (6 x + 3))

Expand

- (6 x - (4 x + 8) = 9 + (6 x + 3)) : - 6 x + (4 x + 8) = 9 - (6 x + 3)

- 6 x + (4 x + 8) = 9 - (6 x + 3)

Expand

= 9 (4 x + 8) : + = 72

- 6 x + = 72 - (6 x + 3)

- (6 x + 3) : - 6 x - 3

- 6 x + = 72 - 6 x - 3

(t - 4 π) (0, 4, 8 π)

\frac{( x + 1 ) ( n ^{2} - 1 )}{2 x - 7}

\frac{- 10 h - h ^{2}}{25 ( 5 + h ) ^{2}}

3 (4 - π) u^{2}

(7 x - 2) (3 x - 8)^{'}

What is expand-(6x-(4x+8)=9+(6x+3)) ?
The solution to expand-(6x-(4x+8)=9+(6x+3)) is -6x+=72-6x-3